Question

Q.2. In the given figure, ABCD is
a rhombus. Find the value of x,y,z.​

Answer 1

Answer:

z = 10 ( all sides of rhombus are equal )

( In a rhombus, diagonals bisect each other at right angles )

so ABO ia right angle triangle

OA²+OA² = AB²

AB = 10

OB = 6

(Pythagoras theorem)

OA² + 6² = 10²

OA² = 10² - 6²

= 100 - 36

= 64

OA² = 64

OA (x) = √64 = 8

OD² = DA² - OA²

DA = 10 ( all sides of rhombus are equal )

OD² = 10² - 8²

= 100 - 64

= 36

OD(y) = √36 = 6

x = 8

y = 6

z = 10

I hope it will helpful.

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