Question

Q-2
In the system shown in figure mo=4kg, and m = 2 kg. The pulleys
are massless and friction is absent everywhere. The acceleration of
block A is (g = 10 m/s)
10/3 m/s2
(2) 20/3 m/s2
(3) 2 m/s
(4) 4 m/s
​

Answer 1

The acceleration of block A is equals to 10/3 m/s²

Given-

• Mass of block B = 4 kg
• Mass of block A = 2 kg
• Pulley is mass less
• Friction is absent

Let the acceleration of block A be "a"

From the attached figure it is very clear that the acceleration of block B is a/2 in downwards direction.

Forces are also shown in the attached figure

Forces in A

(T/2 - mA g sin 30° = mA × a ) 2

Forces in B

mB g - T = mB a/2

By adding both the equations and substituting the values we get

a = 20/6 = 10/3 m/s²

Answer 2

Answer:

10/3 m/s^2

Explanation:

The acceleration of block A is equals to 10/3 m/s²

Given-

Mass of block B = 4 kg

Mass of block A = 2 kg

Pulley is mass less

Friction is absent

Let the acceleration of block A be "a"

From the attached figure it is very clear that the acceleration of block B is a/2 in downwards direction.

Forces are also shown in the attached figure

Forces in A

(T/2 - mA g sin 30° = mA × a ) 2

Forces in B

mB g - T = mB a/2

By adding both the equations and substituting the values we get

a = 20/6 = 10/3 m/s²