Q.2 In triangle ABC, right angled at B, if cot A = root3 find the value of i) sinA cosC + cosA sinC ii) cosA cosC – sinA sinC
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Step-by-step explanation:
1)
AC=2
AB=ROOT3
BC=1
SINA = OPPOSITE /HYPOTENUSE
=1/2
COSC=ADJACENT / HYPOTENUSE
=1/2
(COSA)(SINC)=ROOT3/2 *ROOT3/2
=3/4
SUBSTITUE THE SOLUTIONS
1/2 + 1/2 + 3/4
=7/4
2)DIRECTLY
ROOT3/4+ROOT3/4
2ROOT3/4: IS THE ANSWER
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