Q.2
Match the pair
1
i. Uniform motion
N
Beyond gravitational limit
ii. Escape velocity
a=0 m/s2
Radial towards centre
Joule
Increases with height
m/s
Object at rest
Answers
Answered by
1
Answer:
hello dear/
Explanation:
The g at poles is given by g
p
=
R
2
GM
Now, g at equator, g
e
=
2
g
p
=
2R
2
GM
But, acceleration on body at equator =g
p
−
R
V
2
⇒
R
2
GM
−
R
V
2
=
2R
2
GM
solving, we get V=(
2R
2
GM
)
0.5
Now, escape velocity at poles, V
e
=(
R
2
2GM
)
0.5
=(4×
R
2
GM
)
0.5
=2V.
Similar questions