Q.2 Name the gas evolved in each of the following cases and write the equation involved:
i) Copper carbonate is heated strongly.
(ii) Action of dilute hydrochloric acid on sodium sulphite.
(iii) Nitrogen combines with hydrogen.
(v) Action of dilute sulphuric acid on sodium carbonate.
(v) Addition of sodium to cold water.
Answers
Answer:
(i) This reaction is the thermal decomposition of Copper Carbonate, which breaks down when heated into two or more products from the initial reactant. The products evolved in this particular reaction are Copper Oxide and Carbon Dioxide. Therefore, the gas evolved here is Carbon Dioxide.
Answer:
1.This reaction is the thermal decomposition of Copper Carbonate, which breaks down when heated into two or more products from the initial reactant. The products evolved in this particular reaction are Copper Oxide and Carbon Dioxide. Therefore, the gas evolved here is Carbon Dioxide.
2.When dilute hydrochloric acid reacts with sodium sulphite, sulphur dioxide gas is evolved. The reaction when hydrochloric acid reacts with sodium sulphite, it forms sodium chloride and sulphur dioxide which gives the smell of burning sulphur. It is a colourless gas having the suffocating smell of burning sulphur.
3.Ammonia
When hydrogen gas combines with nitrogen to form Ammonia the following chemical reaction will take place. Our equilibrium reaction will be N2(g) + 3H2(g) ⇔ 2NH3(g) + Heat. In this case, Hydrogen and nitrogen react together to form ammonia
4.When dilute sulphuric acid is added to sodium carbonate, the corresponding salt, sodium sulphate and water are formed and carbon dioxide gas is evolved.
5.When sodium is dropped in cold water, it reacts explosively and burns with a golden yellow flame. The reaction is exothermic and vigourus. It form sodium hydroxide with the liberation of hydrogen gas.
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