Q.2: Show that 1, 2, 3 are zeros of the polynomial f(x) = (x - 1)(x-2)(x-3).
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Answer:
f(x) = (x - 1)(x-2)(x-3).
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f(1) = (1-1)(1-2)(1-3) = 0
0(-1)(-2) = 0
0 = 0
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f(2) = (2-1)(2-2)(2-3) = 0
(1)(0)(-1) = 0
0 = 0
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f(3) = (3-1)(3-2)(3-3) = 0
(2)(1)(0) = 0
0 = 0
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