Question

Q-2 Silver crystallizes in fcc lattice. If the edge length of the cell is 4.07 x 10 cm.
Calculate the atomic radius and density of silver,
(At. mass of Ag =108u, NA = 6.02x1023)​

Answer 1

Answer:

Atomic mass of silver =108u "or" =108 g/mol

Atomic cell length, a=3.0×10

−8

cm

Atomic radius in FCC, r=

4

a

2

=

4

3.0×10

−8

2

=1.06×10

−8

cm

Each silver crystal unit cell contains 4 atom.

Density, d=

N

A

×a

3

4×atomicmassofsilver

=

6.02×10

23

×(3.0×10

−8

)

3

4×108

=26.58g.cm

−3