Math, asked by mastanshareef6769, 1 year ago

Q 2. Solve by suitable rearrangement:
i. 1+2+3+4+996+997+998+999
ii. 4 x 4957 x 100

Answers

Answered by shreya459
31
i. (996+4)+(997+3)+(998+2)+(999+1)
1000+1000+1000+1000
4000
hence, solved

ii. (4957x100)x4
495700x4
1982800
hence,solved

hope this must be useful!!

shreya459: plz mark as brainliest ans
Answered by bhavikatalreja68
0

Answer:

4000

Step-by-step explanation:

first add:-

1+2+3+4=10

then add:-

996+997+998+999= 3990

then add:-

10+3990

YOUR FINAL ANSWER IS 4000

I KNOW I AM SMART AND INTELLIGENT

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