Question

Q.2. Solve p2+q2 = 1​

Answer 1

Answer:

p^2+q^2=1

value:p=0, q=1

(p+q) ^2 =p^2+q^2+2pq

=0+1+2×0×1

=1

Answer 2

Here the values of p=0 then q=1 or -1 and may be p=1 or -1 then q=0

Step-by-step explanation:

This question can be solved by trial and error method by fixing out the available values.

If we go by trial and error method if we fix the value of p as zero then as the power of q is 2 so the value of q can be 1 or -1.

In the same manner if we fix the value of q as zero then the power of p is 2 so, the value of p can be 1 or -1.