Physics, asked by satheshraddha73, 1 month ago

Q.2) The current length 10 cm a is force acting an a straight camoying conductor of parpendicular to magnetic field of 10 ampere find force?

Answers

Answered by sonishreyasoni962

0

Answer:

Correct option is

B

5×10−3

Fˉ=i(l×B)

F=BilSinθ

=0⋅02×5×0⋅1×sin300

=5×10−3N

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