Question

Q.2 The zeroes of x2–2x -8 are: * O (a) (2,-4) 0 (b) (4,-2) O (C) (-2,-2) c O (d) (-4,-4)​

Answer 1

$option: \: (b) \: (4,-2)$

Step-by-step explanation:

$let, \: \: \: {x}^{2} - 2x - 8 = 0 \\ {x}^{2} - 4x + 2x - 8 = 0 \\ x(x - 4) + 2(x - 4) = 0 \\ (x - 4)(x + 2) = 0 \\ x - 4 = 0 \: \: and \: \: x + 2 = 0 \\ x = 4 \: \: and \: \: x = - 2$