Question

Q.2) There are 5 bunglars who went to bakery to rob it. The first robber me it
the total beard and a bread. The second robber again ate of the remaining
bread and a x bread. The 3rd 4th and 5th robber did the same thing. After the
robber there is no bread left. How many bread were there in total?
a)31 b)37 c)23 d)41​

Answer 1

Answer:

First we create a general rule for amount of bread left when each burglar leaves

Lets assume we have x no of bread

At every step x/2 + 1/2 bread is eaten by the burglar

Therefore after each step compared to previous step we have [x-(x/2 + 1/2)] = x/2 - 1/2 bread left.

Now let us go to the problem

Now after 5th burglar leaves we have 0 bread left

Hence number of bread after 4th burglar leaves (or before 5th burglar enters) is calculated by

x/2 - 1/2 = 0

Therefore x = 1

Similarly after 4th burglar leaves we have 1 bread left

Hence number of bread after 3th burglar leaves (or before 4th burglar enters) is calculated by

x/2 - 1/2 = 1

Therefore x = 3

Similarly after 3rd burglar leaves we have 3 bread left

Hence number of bread after 2nd burglar leaves (or before 3rd burglar enters) is calculated by

x/2 - 1/2 = 3

Therefore x = 7

Similarly after 2nd burglar leaves we have 7 bread left

Hence number of bread after 1st burglar leaves (or before 2nd burglar enters) is calculated by

x/2 - 1/2 = 7

Therefore x = 15

Similarly after 1st burglar leaves we have 15 bread left

Hence number of bread before 1st burglar enters is calculated by

x/2 - 1/2 = 15

Therefore x = 31·····························Ans

Step-by-step explanation:

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