Question

Q. 2. There is a current of 40 ampere in a wire of 10-6 m2 area of cross section. If the number
of free electron per mº are 1029, then what will be the drift velocity
A) 250*10 m/s
B) 2.50*10 m/s
C) 1.25*10% m/s
D) 25.0*10 m/s​

Answer 1

Explanation:

V=(

nqA

I

)=

10

29

×1.6×10

−19

×10

−6

40

=

1.6

40

×10

−29+25

V=2.5×10

−2

m/s