Question

Q.2) x2- 2x -8 द्विघातीय बहुपद के शून्यक ज्ञात
कीजिये​

Answer 1

Answer:

ANSWER = (x - 4)(x + 2)

EXPLANATION =

x2 - 2x - 8

= x2 + 2x - 4x - 8 [ x (x+2) - 4(x+2)]

= (x-4)(x+2)