Q. 20 1 point In the given figure, O is the center of a circle in which ZOAB= 20° and ZOCB=50°. Then, ZAOC =? O 20° A B 50° С O (A 50° O (B) 70° (C) 20° ml 60°
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Answer:
We know that OB=OC which is the radius
The base angles of an isosceles triangle are equal
So we get
∠OBC=∠OCB=55
o
In △BOC
Using the angle sum property
∠BOC+∠OCB+∠OBC=180
o
By substituting values
∠BOC+55
o
+55
o
=180
o
On further calculation
∠BOC=180
o
−110
o
So we get
∠BOC=70
o
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