Question

Q 20: A CAR IS MOVING WITH AN
INITIAL VELOCITY OF 10M/S.
WHAT WILL BE ITS FINAL
VELOCITY AFTER 15 SEC, IF ITS
ACCELERATION IS 4M/S2?
Marks :
1
1.
70M/S
2.
30M/S
3.
O M/S
4.
50M/S​

Answer 1

Answer:

(1) 70 m/s

Explanation:

Given:

• Initial velocity of the car = u = 10 m/s
• Time taken = t = 15 seconds
• acceleration of the car = 4 m/s²

To find:

• Final velocity of the car (v)

Using the first equation of motion :

V=u+at

V=10+4×15

V=10+60

V=70 m/s

The final velocity of the car is equal to 70 m/s

Hence option (1) is correct

Extra :

• Second equation of motion= s=ut+1/2 at²
• Third equation of motion = v²-u²=2as

Answer 2

Given:-

• Initial velocity of car (u ) = 10m/s

• Time taken (t) = 15 s

• Acceleration of Car (a) = 4m/s²

To Find:-

• Final velocity of the Car (v).

Solution:-

By using 1st Equation of Motion

⟹ v = u +at

Putting all the values which is given above

⟹ v = 10 + 4×15

⟹ v = 10 + 60

⟹ v = 70 m/s

Therefore, the final velocity of the car is 70 m/s

Hence , Option (1) is the correct answer.

More Information !!

These are the Three Equation of Motion .

(i) v = u +at

(ii) S = ut + 1/2 at²

(iii) v² = u² +2as

here

v is the Final Velocity

u is the initial velocity

a is the acceleration

s is the distance covered

t is the time taken