Q.20 A driver accelerates his car first at the rate of 2.8 m/s2 and then at the rate of 1.4 m/s2.The ratio of two force exerted by the engine in two cases will be:- *
1 point
2.0 N
2.4 N
3.0 N
1.0 N
please help me
Answers
Answered by
1
Given : A driver accelerates his car first at the rate of 2.8 m/s² and then at the rate of 1.4 m/s².
To find : The ratio of two force exerted by the engine in two cases will be.
- R_1 = Case (1)
- R_2 = Case (2)
Calculations :
→ R_1/R_2
→ 2.8/1.4
→ 28/14
→ 2.0 N
Therefore, 2.0N is the ratio of two force exerted by the engine.
Similar questions