Question

Q.20 Find the remainder when x3 + 3x2 + 3x + 1 is divided by
(i) x-2
(ii) x - 3/2​

Answer 1

Step-by-step explanation:

(i) x-2

x-2=0

x= 2

p(x) = x³ + 3x² + 3x + 1

p(2) = (2)³ + 3(2)² + 3(2) + 1

= 8 + 12 + 6 + 1

= 27 = remainder

(ii) x-3/2

x-3/2=0

x= 3/2

p(x) = x³ + 3x² + 3x + 1

= (3/2)³ + 3(3/2)² + 3(3/2) + 1

= 27/8 + 81/8 + 9/2 +1

By taking LCM

27 + 81 + 36 + 8 / 8

= 152/8

= 19