Q.20 Find the remainder when x3 + 3x2 + 3x + 1 is divided by
(i) x-2
(ii) x - 3/2
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Step-by-step explanation:
(i) x-2
x-2=0
x= 2
p(x) = x³ + 3x² + 3x + 1
p(2) = (2)³ + 3(2)² + 3(2) + 1
= 8 + 12 + 6 + 1
= 27 = remainder
(ii) x-3/2
x-3/2=0
x= 3/2
p(x) = x³ + 3x² + 3x + 1
= (3/2)³ + 3(3/2)² + 3(3/2) + 1
= 27/8 + 81/8 + 9/2 +1
By taking LCM
27 + 81 + 36 + 8 / 8
= 152/8
= 19
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