Question

q-20
I WILL MARK THE ANSWER AS BRAINLIEST

Answer 1

Answer:

Step-by-step explanation:

x = (√p+q   +  √p-q)/ (√p+q   - √p-q)

compound and divident method a/b = (a+b)/(a-b)

= (√p+q  + √p-q  + √p+q - √p-q )/  (√p+q  + √p-q  - √p+q + √p-q )

above and below two  terms gets cancelled

= (2√p+q)/(2√p-q)

x = √p+q/√p-q

question : qx²-2px +q

q (( p+q)/(p-q)) - 2p ((√p+q)/(p-q)) + q = 0

get denomiators equal

q ((p+q)/(p-q)) - 2p((p+q)/(p-q))+ q((p-q)/(p-q)) = 0

q(p+q) - 2p(p+q) + q(p-q) = 0

pq + q² - 2p² - 2pq + qp - q² = 0

- 2p²