q.20 if 25th division of vernier scale coincides with 20th division of main scale, then the least count of vernier calliper is (take 1 msd = 1 mm)
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If 1 MSD = 1mm
We have,
25 VSD = 20 MSD
1 VSD = 20/25 MSD = 4/5 MSD
Now,
L.C. = (1- 4/5) MSD = 1/5 value of 1 MSD = 1/5 X 1mm = 0.2 mm = 0.02 mm
We have,
25 VSD = 20 MSD
1 VSD = 20/25 MSD = 4/5 MSD
Now,
L.C. = (1- 4/5) MSD = 1/5 value of 1 MSD = 1/5 X 1mm = 0.2 mm = 0.02 mm
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