Question

Q.20) Jay, Babita, Keshav and Deepa are standing on 4 (different) corners of square. Jay
moves towards Keshav and reaches at his position in 20√2 steps. Now Keshav will reach on
Deepa's position in​

Answer 1

Answer:

20 steps

Step-by-step explanation:

jay deepa

20√2

Babita. keshav

they form a square and jay reached keshav diagonally so

diagonal = a√2

side =20

keshav should reach deepa by a side so , he will reach in 20 steps

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Answer 2

Given :  Jay, Babita, Keshav and Deepa are standing on 4 (different) corners of square. Jay  moves towards Keshav and reaches at his position in 20√2 steps  

To Find : Keshav will reach on  Deepa's position in​ how many steps

Solution:

Let say this  is square with 4 vertex

Jay  , Babita , Keshav & deepa

Sides are :

Jay - Babita

Babita - Keshav

Keshav - deepa

deepa - Jay

Diagonals are

Jai - keshav    

Babita - deepa

Diagonal  = Side√2   in square

Jay  moves towards Keshav and reaches at his position in 20√2 steps

Diagonal   = 20√2

=> Side√2 = 20√2

=> side = 20 steps

Keshav - deepa is side

Hence Keshav will reach on  Deepa's position in​ 20 steps

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