Question

Q 20) Motion of the particle is
given by equation s=(5t+2t
2 +12t + 5)m. The value of
acceleration of the particle at
t=2 sec is *​

Answer 1

Step-by-step explanation:

s= 5t +2t +2+12t+5

a= ds/dt

a = d/dt(s)

a=d/dt(5t+2t+2+12t+5)

a= 5+2+0+12+0 [differentiation]

a= 19m/s2

At t= 2sec the acceleration is 5.2+2.2+2+12.2+5=45m/s2