Q 20 of 60
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At what height above the ground must a
mass of 5kg be to have its PE, equal in
value to the KE possessed by it when it
moves with a velocity of 20m/s? (Assume
g=10m/5)
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Let height be h.
So, PE at that height =mgh
KE of the mass when moving with velocity 10 m/s=1/2 mv
PE=KE
mgh=1/2gv^2
Putting values we get:
10×h=50
h=5m
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