Question

Q-20 State Hooke's law. Deduce expression for young's models of a wire of length l radius cross-section loaded with a body of mass producing an exposure​

Answer 1

Answer:

Hookes law:

within the elastic limit, the stress applied is directly proportional to strain produced.

Explanation:

stress=thrust/area=F/πr^2

strain=change in length/original length=∆l/l

Young's modulus (Y)=stress/strain

=F*l/πr^2*∆l

Answer 2

The young's models of a wire of length l radius cross-section loaded with a body of mass is:

Hooke's law:

• Hooke’s law aims to state that the strain of any material is always proportional to that of the applied stress, that too within the elastic limit of that particular material.

• Therefore, whenever the elastic materials are stretched and the stress is being applied to the object, the atoms and molecules constituting the object shall deform.

• The area of cross-section of a wire is 1/100000 m^2 length of the wire is increased by 0.1% a tension of 1000 N is produced.

• The young's modulus of the wire will be.

• A wire with cross-sectional area 1.00 cm^2 stretches 0.500% of its length when it is stretched with a tension of 20.0 N.