Question

Q.20
The height at which the weight of a body becomes 1/25 times its weight on the
surface of earth (radius R ) is
(a) 4R
(b) 5R
(c) 15 R
(d) 3R

Answer 1

Answer:

a

4R

See Attachment

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Answer 2

Explanation:

GMm/(R+h)^2=1/25(GMm/R^2)

1/(R+h)^2=1/25R^2

(1/R+h)^2=(1/5R)^2

1/R+h=1/5R

5R=R+h

h=4R

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