Q. 20. When 200 gm of H2 and 200 gm of O, is reacted in a closed vessel, calculate mass of
water formed and mass of reactant left.
Q. 21. Find the volume of CO2 evolved when 200 gm of CaCO3 (90% pure) undergoes thermal
decomposition
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Answer:
Q20) 450 g water formed
150 g h2 left
Explanation:
O2 is your limiting reagent
calculate no of moles of o2 = 200/16 = 12.5 mol
now write the equation
2H2 + O2 -> 2h2o
2 vol. 1 vol. 2 vol
2 mol. 1 mol. 2 mol
for every mol of o2 two moles of h2o is formed
therefore for 12.5 mol o2 reacting 25 mol h2o must be formed
25 x 18 (MM of water) = 450g
Hydrogen left -
initially 200g i.e. 100 moles of h2 present
25 moles were used up during reaction
therefore 75 moles i.e 150g is left
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