Question

Q 21. An object is dropped from rest at a height of 150 m and simultaneously
another object is dropped from rest at a height 100 m. What is the difference in
their heights after 2 s if both the objects drop with same accelerations? How
does the difference in heights vary with time?
2​

Answer 1

Answer:

Initial difference in height Δh=150m−100m=50m

Distance for each body with time is given by: s=ut+

2

1

at

2

In the above question both the object are released from rest, so initial velocity is: u=0

Since the object are dropped at same time, so decrease in height is,

s

1

=s

2

=

2

1

gt

2

=20 m

Height of first body after 2 s, h

1

=150−20=130 m

Height of second body after 2 s, h

2

=100−20=80 m

Difference in heights =50 m

Answer 2

Answer:

a good question 30 meter answer