Question

Q.21 If x+p is a factor of p(x) = x-p?x2+2x+p+1 find the value of p​

Answer 1

Answer:

when x2 - 3 y2 = 1 are not only found among its terms, but the numbers x ... we can try u = p - q and v = p + q. ... find polynomials involving any number m whose square is the sum of two

Answer 2

Answer:

For finding the remainder we need to use remainder theorem

Let p(x)=x

2

+px+3−p

As x+p is a factor of p(x), we need to equate it to 0 and put that value of x in p(x).

So, x+p=0

or, x=−p

As, −p is a zero of p(x), so,

p(−p)=(−p)

2

+p(−p)+3−p=0

⇒p

2

−p

2

+3−p=0

or, p=3