Question

Q.21.In bi-prism experiment, the distance
between slit and screen is 1m and distance
between two virtual images of the slit is
0.75mm. If the fringe width is 0.8mm, then
the wavelength of light used is *​

Answer 1

Explanation:

Given,

The distance between the two virtual images of the slit, d=0.1cm

The distance between the slit and the screen, D=1cm

Band Width, X=0.058cm

We have to find out the wavelength of the monochromatic light,

That is, λ=

D

Xd

Substituting the values in the given eqution

That is, λ=

1

0.058×0.1

=0.0058cm