Science, asked by kushwahbetal8, 2 months ago

Q.21 What is surplus? How it can be beneficial for for farmers​

Answers

Answered by XxJAHANGIRxX
1

Explanation:

hii

\LARGE{\bf{\underline{\underline{GIVEN:-}}}}

GIVEN:−

\sf \bullet \ \ \dfrac{(1+sinA-cosA)^2}{(1+sinA+cosA)^2}∙

(1+sinA+cosA)

2

(1+sinA−cosA)

2

\LARGE{\bf{\underline{\underline{SOLUTION:-}}}}

SOLUTION:−

LHS:

\sf \to \dfrac{(1+sinA-cosA)^2}{(1+sinA+cosA)^2}→

(1+sinA+cosA)

2

(1+sinA−cosA)

2

Expand the fractions using .

\sf \to \dfrac{(cos^2-2sincos+sin^2-2cos+2sin+1)}{(cos^2+2sincos+sin^2+2cos+2sin+1)}→

(cos

2

+2sincos+sin

2

+2cos+2sin+1)

(cos

2

−2sincos+sin

2

−2cos+2sin+1)

Rearrange the terms.

\sf \to \dfrac{(cos^2+sin^2-2sincos-2cos+2sin+1)}{(cos^2+sin^2+2sincos+2cos+2sin+1)}→

(cos

2

+sin

2

+2sincos+2cos+2sin+1)

(cos

2

+sin

2

−2sincos−2cos+2sin+1)

We know that cos²A+sin²A=1.

\sf \to \dfrac{1-2sincos-2cos}{2sin+1}→

2sin+1

1−2sincos−2cos

Now here, take -2cos common from the numerator and +2cos common from the denominator.

\sf \to \dfrac{1-2cos(sin+2)}{2sin+1}→

2sin+1

1−2cos(sin+2)

Now, rearrange the terms, add 1 and 1 and take 2 common.

\to\sf\dfrac{1+1+2sin-2cos}{sin+1}→

sin+1

1+1+2sin−2cos

\to\sf\dfrac{2+2sin-2cos}{sin+1}→

sin+1

2+2sin−2cos

Take 2 common.

\to \sf \dfrac{ 2(1+sin) -2cos(sin+1) }{ 2(1+sin) + 2cos(sin +1 ) }→

2(1+sin)+2cos(sin+1)

2(1+sin)−2cos(sin+1)

Take (1+sin) common.

\to \sf \dfrac{ \not{2}\cancel{(1+sin)}(1 - cos) }{\not{2}\cancel{(1+sin )}(1 + cos )}→

2

(1+sin)

(1+cos)

2

(1+sin)

(1−cos)

\to \sf{\red{\dfrac{1-cosA}{1+cosA} }}→

1+cosA

1−cosA

LHS=RHS.

HENCE PROVED!

FUNDAMENTAL TRIGONOMETRIC RATIOS:

\begin{gathered} \begin{gathered}\begin{gathered}\boxed{\substack{\displaystyle \sf sin^2 \theta+cos^2 \theta = 1 \\\\ \displaystyle \sf 1+cot^2 \theta=cosec^2 \theta \\\\ \displaystyle \sf 1+tan^2 \theta=sec^2 \theta}}\end{gathered}\end{gathered}\end{gathered}

sin

2

θ+cos

2

θ=1

1+cot

2

θ=cosec

2

θ

1+tan

2

θ=sec

2

θ

T-RATIOS:

\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3} }{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }& 1 & \sqrt{3} & \rm Not \: De fined \\ \\ \rm cosec A & \rm Not \: De fined & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm Not \: De fined \\ \\ \rm cot A & \rm Not \: De fined & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered}

∠A

sinA

cosA

tanA

cosecA

secA

cotA

0

0

1

0

NotDefined

1

NotDefined

30

2

1

2

3

3

1

2

3

2

3

45

2

1

2

1

1

2

2

1

60

2

3

2

1

3

3

2

2

3

1

90

1

0

NotDefined

1

NotDefined

0

Answered by raijada83
2

Answer:

an amount is extra or more and unit is called surplus.

they retain a part of the need for the families consumption and sell the surplus wheat.

small farmers have little surplus wheat because their total production is small and from the substantial share is kept for their own family need

Explanation:

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