Question

Q 22/60 Molarity of pure water, assuming density of water to be 1 g
cm-3, is
O 1 M
1000
18
M
1M
M
18
18
- М
1000​

Answer 1

Answer:

55.56 M

Explanation:

Molarity is defined as the number of moles of the solute per litre of solution.

Molarity=

Volume of solution in litre

No of moles of solute

We are given that the density of water is 1g/ml. This is equal to $$ 1 Kg/ L $$.

Therefore, the mass of 1L of water will be:

= Density of water × Volume

=1

L

Kg

×1L

=1Kg

=1000g

Therefore, number of moles in 1Kg of water =

molarmass

mass

=

18

1000

=55.56

Therefore, molarity of water = =

1L

55.56moles

=55.56 M