q 22 and ans is 70° steps required
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Here , PL and PM are the tangents of the Circle.
Therefore, OQ is perpendicular to PL
and, OR is perpendicular to PM
Now, In ∆OQS,
OQ = OS
Angle OQS = Angle OSQ = 40°
Now, In ∆OSR,
OS = OR
Angle ORS = Angle OSR = 30°
Therefore,
Angle OSQ + Angle OSR = 40° + 30° = 70°
Therefore, OQ is perpendicular to PL
and, OR is perpendicular to PM
Now, In ∆OQS,
OQ = OS
Angle OQS = Angle OSQ = 40°
Now, In ∆OSR,
OS = OR
Angle ORS = Angle OSR = 30°
Therefore,
Angle OSQ + Angle OSR = 40° + 30° = 70°
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