Q.22 plz solve it's urgent plz
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All will be cancelled and answer will be one
manyadd777:
Bhai yar pura solve kar na page pe plz
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The identity to be used here is
![{a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} ) {a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} )](https://tex.z-dn.net/?f=+%7Ba%7D%5E%7B3%7D+%2B+%7Bb%7D%5E%7B3%7D+%3D+%28a+%2B+b%29%28+%7Ba%7D%5E%7B2%7D+-+ab+%2B+%7Bb%7D%5E%7B2%7D+%29)
Put a = 0.87 and b = 0.13 and expand the numerator using the identity
![LHS \\ \\ = \frac{ {(0.87)}^{3} + {(0.13)}^{3} }{ {(0.87)}^{2} - 0.87 \times 0.13 + {(0.13)}^{2} } \\ \\ = \frac{ (0.87 + 0.13)\ [{(0.87)}^{2} - 0.87 \times 0.13 + {(0.13)}^{2}]}{ {(0.87)}^{2} - 0.87 \times 0.13 + {(0.13)}^{2} } LHS \\ \\ = \frac{ {(0.87)}^{3} + {(0.13)}^{3} }{ {(0.87)}^{2} - 0.87 \times 0.13 + {(0.13)}^{2} } \\ \\ = \frac{ (0.87 + 0.13)\ [{(0.87)}^{2} - 0.87 \times 0.13 + {(0.13)}^{2}]}{ {(0.87)}^{2} - 0.87 \times 0.13 + {(0.13)}^{2} }](https://tex.z-dn.net/?f=+LHS+%5C%5C+%5C%5C+%3D+%5Cfrac%7B+%7B%280.87%29%7D%5E%7B3%7D+%2B+%7B%280.13%29%7D%5E%7B3%7D+%7D%7B+%7B%280.87%29%7D%5E%7B2%7D+-+0.87+%5Ctimes+0.13+%2B+%7B%280.13%29%7D%5E%7B2%7D+%7D+%5C%5C+%5C%5C+%3D+%5Cfrac%7B+%280.87+%2B+0.13%29%5C+%5B%7B%280.87%29%7D%5E%7B2%7D+-+0.87+%5Ctimes+0.13+%2B+%7B%280.13%29%7D%5E%7B2%7D%5D%7D%7B+%7B%280.87%29%7D%5E%7B2%7D+-+0.87+%5Ctimes+0.13+%2B+%7B%280.13%29%7D%5E%7B2%7D+%7D+)
Put a = 0.87 and b = 0.13 and expand the numerator using the identity
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