Question

Q.22) What should be the diameter of a water drop so that the excess pressure inside it is 80N/m^(2) (Surface tension of water =7.27times10^(-2)N/m^(*)

Answer 1

Explanation:

∆p =4T/R

R=4T/∆p

R = (4*7.27*10^-2)/80

R = 0.365*10^-2

or the diameter will be 2R = 2*0.365*10^-2 = 0.730*10^-2 m