Q.23 calculate the molarity of solution of ethanol in water in which mole fraction of ethanol is 0.040. ( ⭕️density of water = 1g/cm3⭕️) in this ⭕️ the condition is very important so when you searched on Google it will gave the answer in condition of density of water is one but in this question the condition is changed
so plzzz give me right✔️ answer
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Explanation:
The mole fraction of ethanol is equal to the ratio of the number of moles of ethanol to the total number of moles present in the solution.
For dilute solutions, 1 L of water (or 1 L of solution) contains
18
1000
=55.55 moles of water.
Let n be the number of moles of ethanol. The mole fraction of ethanol is 0.040.
Hence, 0.040=
n+55.55
n=0.040n+2.222
n=1−0.040
2.222
=2.31 moles.
The molarity of the solution is the ratio of the number of moles of solute present in 1 L of solution.
As 1 L of solution contains 2.31 moles of ethanol, the molarity of a solution is 2.31 M.
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