Question

Q.23 With a neat labelled circuit diagram, explain
working of P-N junction diode as a full-wave
rectifier​

Answer 1

Answer:

The AC input voltage across secondary s1 and s2 changes polarity after each half cycle. Suppose during the first half cycle of input AC signal, the terminal s1 is positive relative to centre tap O and s2 is negative relative to O. Then diode D1 is forward biased and diode D2 is reverse biased. Therefore, diode D1 conducts while diode D2 does not. The direction of current (i1) due to diode D1 in load resistance RL is directed from A to B. In next half cycle, the terminal s1 is negative and s2 is positive relative to centre tap O. The diode D1 is reverse biased and diode D2 is forward biased. Therefore, diode D2 conducts while D1 does not. The direction of current (i2 ) due to diode D2 in load resistance RL is still from A to B. Thus the current in load resistance RL is in the same direction for both half cycles of input AC voltage. Thus for input AC signal the output current is a continuous series of unidirectional pulses. In a full wave rectifier, if input frequency is f hertz, then output frequency will be 2f hertz because for each cycle of input, two positive half cycles of output are obtained. (b) Output waveforms for the following inputs A and B of OR gate and NAND gate. Read more on Sarthaks.com - https://www.sarthaks.com/58211/circuit-diagram-rectifier-using-junction-diode-explain-working-output-input-waveforms