Question

Q.24 *
2 points
Q.24 If x + y = 12 and xy = 14, find the value of x² + y2
O 144
16
O
116
O 26​

Answer 1

Answer:

(x+y)^2

x^2+y^2+2xy

A.T.Q

xy=14

then

x^2+y^2+2×14

x^2+y^2+28

x^2+y^2=-28

Answer 2

The answer of this question as $x^{2} +y^{2}$  (c) 116.

Step-by-step explanation:

We are given with two linear equations,

$x+y=12$

$xy=14$

and we have to find the value of $x^{2} +y^{2}$ .

• Formula used,

$(x+y)^{2} =x^{2} +y^{2} +2xy$

• Calculation for $x^{2} +y^{2}$ ,

we have,

$x+y=12$

$xy=14$

We can find the value of  $x^{2} +y^{2}$  by using formula,

$(x+y)^{2} =x^{2} +y^{2} +2xy$

we have values of $(x+y)$ and $xy,$ by putting required values we get,

$(12)^{2} =x^{2} +y^{2} +2*(14)$

$144 =x^{2} +y^{2} +28$

$x^{2} +y^{2} =144-28$

$x^{2} +y^{2} =116$

In this way we get the answer as $x^{2} +y^{2} =116$.