Question

Q.24 - allows better internal circulation of air in aquatic plants. a. Stomata b. Cuticles c. Aerenchyma d. Water
please answer fast it is argent I will mark you please don't spam​

Answer 1

Answer:

Given length of swimming pool =20m

Given length of swimming pool =20mBreadth of swimming pool =15m

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4m

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h=2[20+15]×4

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h=2[20+15]×4=2×35×4

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h=2[20+15]×4=2×35×4CSA of cuboid (pool)=280m

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h=2[20+15]×4=2×35×4CSA of cuboid (pool)=280m 2

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h=2[20+15]×4=2×35×4CSA of cuboid (pool)=280m 2

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h=2[20+15]×4=2×35×4CSA of cuboid (pool)=280m 2 If cost of painting is =20 Rs/sq. m

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h=2[20+15]×4=2×35×4CSA of cuboid (pool)=280m 2 If cost of painting is =20 Rs/sq. mthen cost of painting four walls of pool =20×280

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h=2[20+15]×4=2×35×4CSA of cuboid (pool)=280m 2 If cost of painting is =20 Rs/sq. mthen cost of painting four walls of pool =20×280Cost =5600Rs.

Given length of swimming pool =20mBreadth of swimming pool =15mHeight of swimming pool =4mCurved surface area of cuboid =2(l+b)h=2[20+15]×4=2×35×4CSA of cuboid (pool)=280m 2 If cost of painting is =20 Rs/sq. mthen cost of painting four walls of pool =20×280Cost =5600Rs.Hence cost of painting four walls of swimming pool is Rs. 5600.

Answer 2

Answer:

plz mark my answer brainliest