Question

Q 24 Find the area of a rhombus whose side is 5 cm and its altiude is 4 cm. If one of its diagonal is 8 cm long, find the length of the
other diagonals​

Answer 1

${\underline {\underline{\Large {\bf \green {Solution:-} }}}}$

Area of the rhombus = Side × Length of the altitude 

= 5*4.8

= 24 sq cm 

Now,

Let the length of the other diagonal = x

It is known that the area of a rhombus is half the product of its diagonals. 

∴ (1/2) × 8 × x = 24

⇒ 4x = 24

⇒ x = 6 cm

The length of the other diagonal is 6 cm.

Answer 2

Answer:

Area of rhombus = Base × Height =  

2

1

​  

×Product of diagonals

⇒5×4.8=  

2

1

​  

×(8×x)

⇒24=  

2

1

​  

×(8×x)

⇒x=6 cm