Question

Q. 24 of 54
Mark for review
The active ingredient in aspirin is acetyl
salicylic acid (molecular formula C,H,04) with
K. = 4.0x10". The pH of the solution obtained
by dissolving two aspirin tablets (containing
0.36 g of acetyl salicylic acid in each tablet)
in 250 ml of water is (log 2 = 0.3)​

Answer 1

Answer:

i think it is practice paper or exam paper this is brainly so what we have doubts that only we should use the brainly not only that too answer the questions but not exam or practoce paper question it's not my demand not my order i am just saying i my guess correct it is practice paper no

Explanation:

if i said any wrong i am extremely sorry sister or brother