Question

Q.24 Solve the following equations:
3(y-2) = 2(y - 1) - 3​

Answer 1

Answer:

hope this may help u....

Answer 2

3(y-2) = 2(y-1) - 3

3y - 6 = 2y - 2 - 3

3y - 6 = 2y - 5

3y - 2y = (-5) + 6

y = 1

Verification:

substituting y for 1,

3(y-2) = 2(y-1)-3

3(1-2) = 2(1-1) - 3

3(-1) = 2(0) - 3

-3 = 0-3

LHS = RHS

hence verified

hope it helps

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