Question

Q:24???
what must be subtracted from x to the power cube minus 6 into X ^ 2 - 15 into X + 80 so that the result is exactly divisible by x to the power 2 + X - 12?​

Answer 1

Answer:

x^3-7x^2-16x+92

Step-by-step explanation:

let A is subtracted from x^3-6x^2-15x+80

x^3-6x^2-15x+80 -A= x^2+x-12

A= x^2+x-12-x^3+6x^2+15x-80

A= x^3-7x^2-16x+92

if we minus x^3-7x^2-16x+92 from x^3-6x^2-15x+80 we get

x^3-6x^2-15x+80 - (x^3-7x^2-16x+92)

= x^3-6x^2-15x+80-x^3+7x^2+16x-92

= x^2 + x- 12 is completely divisible by x^2 + x- 12