Q.25 Divide 150 into three parts such that the second number is five sixths the first and the third
number is four fifths the second.
Answers
Answered by
1
Answer: The lengths are 60,50, and 40
Step-by-step explanation:
Answer
Let the 3 parts be a,b, and c
Given: First part:x
second part 6/5 of x is 5x/6
Third part 4/5 of second part is = 150
- x + 5x/6 + 2x/3 = 150
- 6x +5x + 4x = 6 x 150
- 15 x = 6 x 150
- x = 6x 150/15 = 60
three parts of 150 are respectively
First part=60
Second part= 5/6(x) = 5/6 x 60 = 50
Third part=150−Sum of other two parts=150−(60+50)=40
∴The lengths are 60,50, and 40
Answered by
1
Answer:
60,50,40
Step-by-step explanation:
let first number be x
then second number = 5x/6
third number = 4/5 X 5x/6 = 2x/3
x + 5x/6 + 2x/3 = 150
6x/6 + 5x/6 + 4x/6 = 150
15x/6 = 150
15x = 150 X 6
15x = 900
x = 900/15
x = 60
so,
first number= x = 60
second number = 5x/6 = 5 X 60/6 = 50
third number = 2x/3 = 2 X 60/3 = 40
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