Question

Q.25. Find a quadratic polynomial whose zeroes are 5-3-12 and 5 +3-12
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Answer 1

Answer:

$x^{2} -10x-200$

Step-by-step explanation:

zeros are,

5-3-12 = -10

5+3+12 = 20

Sum of zeros = -10+20 = 10 = -b/a

Product of zeros = -10*20 = -200 = c/a

therefore, a=1; b= -10; c=-200