Question

Q 25 The x and y-intercepts of graph 8x + 14y = 56 are:
Ops:
0 7 units and 4 units
O 4 units and 7 units
C.
O 0 units and 3 units
3 units and O units​

Answer 1

$Given\: linear \: equation \: in \: two \\variables \: x \: and \: y \: is \: 8x + 14 y= 56$

$Dividing \: each \: term \: by \: 56, we \: get$

$\implies \frac{8x}{56} + \frac{14y}{56} = \frac{56}{56}$

$\implies \frac{x}{7} + \frac{y}{4} = 1$

$\green { x - intercept (a) = 7}$

$\green {y - intercept (b) = 4}$

/* We know that */

$\underline{\blue{ Two \: intercepts \: form : }}$

$\boxed{ \pink{ \frac{x}{a} + \frac{y}{b} = 1 }}$

$Where , x - intercept (a) = 7$

$y - intercept (b) = 4$

Therefore.,

$\green { First \: option \: is \: correct. }$

•••♪

Answer 2

Answer:    (A.) 7 units and 4 units

Step-by-step explanation:

GIVEN :  Linear equation with two variable -  8x + 14y = 56

TO FIND : x and y intercepts

SOLUTION :

                we are given the equation , to find the intercepts we need to make the constant "1". So, for that lets divide the whole equation by 56

          ∴ $\frac{8x}{56}$ + $\frac{14y}{56}$ = $\frac{56}{56}$

         $\frac{x}{7}$ + $\frac{y}{4}$ = 1

As we know two intercepts form ,

$\frac{x}{a}$ + $\frac{y}{b}$ = 1

Here , a = 7  and b = 4

So, x - intercept (a) = 7

      y - intercept (b) = 4

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