Question

(Q) 26 cards each bearing one English letter are kept in a box. One card is drawn at
random. What is the probability that the card drawn is a vowel card?​

Answer 1

Step-by-step explanation:

n(s)=26

let A be the event to get a vovel card

A=[A,E,I,O,U]

n(A)=5

p(A)=n(A)/n(S)

=5/26

so,

therefore 5/26 is the probability to get a vovel card in the deak

Answer 2

Given,

Number of cards kept in a box, bearing one English letter each = 26

To find,

The probability that the card drawn randomly is a vowel card.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

The probability of occurrence of a favorable event = P (favorable event)

= (Total number of occurrence of the favorable event) / (Total number of occurrence of all possible events)

= (Total number of occurrence of the favorable event) / (Total number of trials)

As per the given question;

The favorable event is the occurrence of a vowel, that is either A, E, I, O, or U, respectively.

So, the number of favorable events = 5 {A, E, I, O, U}

And, the total number of trials

= total number of cards

= total number of alphabets = 26

Now,

The probability that the card drawn randomly is a vowel card

= (Total number of occurrence of the favorable event) / (Total number of trials)

= (Total number favorable events) / (Total number of cards)

= Total number of vowels / total number of alphabets

= 5/26 = 0.19 approx

Hence, the probability that the card drawn randomly is a vowel card is equal to 5/26, which is approximately equals to 0.19.