Question

Q.26 Find three consecutive positive integers such that the sum of the second and the third number
Exceed the first by 14.
​

Answer 1

Answer:

So the three numbers are 8 , 10 and 12

Step-by-step explanation:

Let the 3 consecutive positive integers be x , x + 2 and x + 4

Sum of second and third numbers = (x + 2) + (x + 4) = 2x + 6

It is given that the sum of the second and the third number  exceeds the first by 14

So (2x + 6) - 14 = x

=> 2x - 8 = x

=> 2x - x = 8

=> x = 8

So the three numbers are x , x + 2 , x + 4

= 8 , 8 + 2 , 8 + 4

= 8 , 10 , 12

                                               VERIFICATION :

Sum of 2nd and 3rd numbers = 10 + 12 = 22

22 - 8 = 14

Hence verified