Q:26. IF tanA =)/4 then find the value of 1/SinA + 1/CosA
Answers
Answered by
2
Answer:
tanA = 3434 = 3k4k3k4k sinA = 3k5k3k5k = 3535, cosA = 4k5k4k5k = 4545 1sinA+1cosA1sinA+1cosA = 53+5453+54 = (20+15)12(20+15)12 = 3512
Answered by
0
Answer:
Given, tanA=
12
5
=
AB
BC
∴AC=AB
2
+BC
2
⇒AC
2
=5
2
+(12)
2
⇒AC
2
=25+144
⇒AC
2
=169
⇒AC=13
Now, sinA=
AC
BC
=
13
5
cosA=
AC
AB
=
13
12
∴sinA+cosA
=
13
5
+
13
12
=
13
5+12
=
13
17
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