Question

Q-26) The equation of the line joining the points (2, 4) and parallel to the line 9x + 3y = 2​

Answer 1

Two parallel lines have equal slope. Therefore, slope of line 9x + 3y = 2 is equal to the slope of the line joining the points (2, 4).

Slope of line is given as :-

$\sf m = - \: \dfrac{coefficient \: of \: x}{coefficient \: of \: y}$

Where, m = slope

Slope of line 9x + 3y = 2 :-

$\implies \sf \: m = \dfrac{ - 9}{3}$

$\implies \sf \: m = - 3$

Slope of the line joining the point (2, 4) = -3

Now equation of line passing through the point (2, 4) and having slope -3 :-

$\implies \sf y - 4 = (x - 2)( - 3)$

$\implies \sf y - 4 = - 3x + 6$

$\implies \sf y +3x - 4 - 6 = 0$

$\implies \sf y +3x - 10 = 0$

Answer :

The equation of the line joining the points (2, 4) and parallel to the line 9x + 3y = 2 :- y+3x-10=0