Question

Q.27. find the 11th term from the last term (towards the first term )of the
AP: 10, 7, 4, .........
......... -62​

Answer 1

Answer:

27,23,19,..........,−65

If we reverse the series

1st term =−65

Last term =27

=>d=±4

t11=−65+(11−4)4

       =−65+40=−25

Answer 2

Answer:

Explanation:

Given :

• AP : 10 , 7 , 4 ,.......... -62.

To Find :

• 11th term of an AP.

Formula to be used :

• nth term of an AP, ie,, an = a + (n - 1)d

Solution :

Given, AP : 10 , 7 , 4 ,.......... -62.

★First term,

⇒ a = 10

★Common difference,

⇒d = t² - t¹

⇒d = 7 - 10

⇒d = -3

★11th term of an AP,

an = a + (n - 1)d

⇒ a11 = 10 + (11 - 1) × -3

⇒ a11 = 10 + 10 × -3

⇒ a11 = 10 - 30

⇒ a11 = -20

Hence, 11th term of an AP is -20.